A) 8 V
B) 6 V
C) 4 V
D) \[\frac{8}{3}\,V\]
Correct Answer: A
Solution :
The given circuit is simplified as \[\therefore \] \[C=\frac{4.5\times 9}{4.5+9}=3\mu F\] \[\therefore \] \[Q=CV=3\times 12=36\,\mu C\] Now, the Potential diff. across\[4.5\,\mu C\]capacitor is \[V=\frac{36\,\mu C}{4.5\,\mu F}=8V\] Hence, the correction option is [a].You need to login to perform this action.
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