A) 0.15 m
B) 0.12 m
C) 1.5 m
D) 0.5 m
Correct Answer: A
Solution :
Loss of KE = Gain in elastic PE \[\frac{1}{2}m{{v}^{2}}=\frac{1}{2}K{{x}^{2}}\] or, \[0.5\times {{(1.5)}^{2}}=50\times {{x}^{2}}\]\[\therefore \]\[{{x}^{2}}\frac{{{(1.5)}^{2}}}{100}\] or, \[x=0.15\,m\] Hence, the correction option is [a].You need to login to perform this action.
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