A) \[\frac{qQ}{4\pi {{\varepsilon }_{0}}L}\]
B) \[\frac{qQ}{2\pi {{\varepsilon }_{0}}L}\]
C) \[\frac{qQ}{6\pi {{\varepsilon }_{0}}L}\]
D) \[\frac{qQ}{6\pi {{\varepsilon }_{0}}L}\]
Correct Answer: D
Solution :
Work done is equal to change in potential energy. In 1st case, when charge +Q is situated at C.You need to login to perform this action.
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