A) \[\frac{4\pi q}{6(4\pi {{\varepsilon }_{0}})}\]
B) \[\frac{4\pi q}{6(4\pi {{\varepsilon }_{0}})}\]
C) \[\frac{q}{6(4\pi {{\varepsilon }_{0}})}\]
D) \[\frac{2\pi q}{6(4\pi {{\varepsilon }_{0}})}\]
Correct Answer: A
Solution :
This problem can be solved by symmetry consideration and Gauss Law. The total flux passing through the close cube \[\phi =\frac{q}{{{\varepsilon }_{0}}}.\] All the six surfaces are symmetrical with respect to charge, hence they will have equal contribution of the flux. So, flux through any one face: \[\phi '=\frac{\phi }{6}=\frac{q}{6{{\varepsilon }_{0}}}.\] \[{{\phi }_{face}}=\frac{q}{6{{\varepsilon }_{0}}}=\frac{4\pi q}{6(4\pi {{\varepsilon }_{0}})}\]You need to login to perform this action.
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