A)
B)
C)
D)
Correct Answer: D
Solution :
We know induced emf \[e=-L\frac{di}{dt}\] During 0 to \[\frac{T}{4},\frac{di}{dt}=cons\tan t\] So, induced emf \[e=-ve\] For \[\frac{T}{4}\]to \[\frac{T}{2},\frac{di}{dt}=0\] Induced emf \[e=0\] For \[\frac{T}{2}\]to \[\frac{3T}{4},\frac{di}{dt}=cons\tan t\] So induced emf \[e=+ve\]You need to login to perform this action.
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