A) \[20\,\Omega \]
B) \[2\,\Omega \]
C) \[0.2\,\,\Omega \]
D) \[2\,k\Omega \]
Correct Answer: B
Solution :
The potential difference across ammeter and shunt is the same. Let\[{{i}_{a}}\]is the current. Flowing through ammeter and \[i\] is the total current. So, a current \[i-{{i}_{a}}\] will flow through shunt resistance. Potential difference across ammeter and shunt resistance is the same. That \[{{i}_{a}}\times R=(i-{{i}_{a}})\times S\] or \[S=\frac{{{i}_{a}}R}{i-{{i}_{a}}}\] Given,\[{{i}_{a}}=1000\,A,i=750\,A,R=13\,\Omega \] Hence,\[\frac{100\times 13}{750}=2\Omega \]You need to login to perform this action.
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