A) 1 mg
B) 2 mg
C) 4 mg
D) 8 mg
Correct Answer: B
Solution :
\[T=49.2\,yr;\,{{t}_{1/2}}=12.3\]year \[\therefore \] \[n=4\] Now, \[N=\frac{{{N}_{0}}}{{{2}^{n}}}=\frac{32}{{{2}^{4}}}=2\,mg\]You need to login to perform this action.
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