A) 1.5 mm
B) 9 mm
C) 6 mm
D) 3 mm
Correct Answer: B
Solution :
Distance of the nth bright fringe from the centre \[{{x}_{n}}=\frac{n\lambda D}{d}\] \[\Rightarrow \] \[{{x}_{3}}=\frac{3\times 6000\times {{10}^{-10}}\times 2.5}{0.5\times {{10}^{-3}}}\] \[=9\times {{10}^{-3}}m=9\,mm\]You need to login to perform this action.
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