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NEET Sample Paper NEET Sample Test Paper-26

  • question_answer
    The least count of stopwatch is \[1/5s\]. The time of 20 ascillations of a pendulum is measured to be 25s. The minimum percentage error in the measurement of time will be

    A)  \[0.1%\]                     

    B)  \[0.8%\]

    C)  \[1.8%\]                     

    D)  \[8%\]

    Correct Answer: B

    Solution :

    Error (%) in time period \[T=\frac{\Delta T}{T}\times 100\] \[=\frac{1/5}{25}\times 100=0.8%\]


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