A) 250
B) 196
C) 392
D) 384
Correct Answer: C
Solution :
\[\begin{matrix} HA \\ C \\ C(1-\alpha ) \\ \end{matrix}\,\,\,\,\begin{matrix} \\ {} \\ {} \\ \end{matrix}\,\,\,\begin{matrix} {{H}^{+}} \\ 0 \\ C.\alpha \\ \end{matrix}\,\,\,\begin{matrix} + \\ {} \\ {} \\ \end{matrix}\,\,\,\begin{matrix} {{A}^{-}} \\ 0 \\ C.\alpha \\ \end{matrix}\] \[K=\frac{C\alpha \,\,.\,\,C\alpha }{C(1-\alpha )}=\frac{C{{\alpha }^{2}}}{1-\alpha }=C{{\alpha }^{2}}\] \[25\times {{10}^{-6}}={{10}^{-2}}\times {{\alpha }^{2}}\] \[\alpha =5\times {{10}^{-2}}\] \[\alpha =\frac{{{\wedge }^{c}}}{{{\wedge }^{o}}}\] \[{{\wedge }^{o}}=\frac{{{\wedge }^{c}}}{\alpha }=\frac{19.6}{5\times {{10}^{-2}}}=392{{\Omega }^{-1}}c{{m}^{2}}\]You need to login to perform this action.
You will be redirected in
3 sec