A) pH increases by 2 units
B) pH decreases by 2 units
C) pH remains unaltered
D) pH decreases by 1 units
Correct Answer: B
Solution :
\[pH=-\log \,\,[{{H}^{+}}]\] \[=-\log \,x\] For 100 times increase in \[[{{H}^{+}}]\] \[pH=-\log [100x]\] \[=-\log x-\log 100\] \[=-\log x-2\] i.e. pH decreases by 2 units.You need to login to perform this action.
You will be redirected in
3 sec