A) \[{{10}^{3}}wb/{{m}^{2}}\]
B) \[{{10}^{5}}wb/{{m}^{2}}\]
C) \[{{10}^{16}}wb/{{m}^{2}}\]
D) \[{{10}^{-3}}wb/{{m}^{2}}\]
Correct Answer: A
Solution :
As the net force on the charge \[F={{F}_{e}}+{{F}_{m}}=0\] \[\Rightarrow \] \[F=qE+q\,(V\times B)=0\] \[\Rightarrow \] \[B=\frac{E}{V}={{10}^{3}}wb/{{m}^{2}}\]You need to login to perform this action.
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