A) The particle is acted upon by a variable force.
B) The speed of particle is maximum at \[X=2m\].
C) The minimum potential energy during the motion is\[20J\].
D) The period of oscillation of the particle is \[\pi /5s\].
Correct Answer: C
Solution :
As,\[f=-\frac{dV}{dX}=-5(2\times 4)\] at mean position \[f=0,\,\,X=2m\] \[{{U}_{\min }}=-20J\] as \[F\propto X\] and \[K=10N/m\] \[\Rightarrow \] \[T=\frac{\pi }{5}S\] (Note that U to be minimum when), \[\frac{dU}{dX}=0\]You need to login to perform this action.
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