A) 50 min
B) 45 min
C) 49 min
D) 48 min
Correct Answer: D
Solution :
\[k=\frac{2.303}{t}\log \frac{a}{a-x}\] \[k=\frac{2.303}{32}\log \frac{a}{a-0.99a}\] \[=\frac{2.303}{32}\log {{10}^{2}}=\frac{2.303}{16}{{\min }^{-1}}\] \[{{t}_{99.9}}=\frac{2.303}{k}\log \frac{a}{a-0.999a}\] \[=\frac{2.303}{k}\log {{10}^{3}}=\frac{3\times 2.303}{2.303}\times 16\] \[{{t}_{99.9%}}=48\min \]
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