A) 5cm leftward
B) 5cm rightward
C) 7cm leftward
D) 7cm rightward
Correct Answer: B
Solution :
As there is no external force acting' on the boat-mass system \[\Rightarrow \] X-coordinate of its centre of mass will remain unchanged i.e., \[\Delta {{X}_{cm}}=0\] \[\Rightarrow \] Initial X-coordinate of the system = final X-coordinate of the system. Let d ^ distance parallel by boat in right ward direction Then, \[\frac{60x+70(x+2)+70(x+1)}{200}\] \[=\frac{60+70+70\,(x+1+d)}{200}\] on solving we get \[x=\frac{10}{200}m=5cm\]You need to login to perform this action.
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