A) \[1:1\]
B) \[1:2\]
C) \[1:4\]
D) \[2:1\]
Correct Answer: A
Solution :
For the first Bohr orbit of hydrogen atom \[mVr=\frac{b}{2\pi }\] \[\Rightarrow \] \[2\pi r=\frac{h}{mV}\] de-Broglie wavelength of electron having same Velocity, \[\lambda =\frac{h}{mV}\] \[\therefore \] \[\frac{2\pi r}{\lambda }=1.\] (As the length of circumference is \[n\lambda =2\pi r\] and it, \[n=1\] then, \[\lambda =2\pi r\]).You need to login to perform this action.
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