A) 1
B) 2
C) 3
D) 4
Correct Answer: B
Solution :
For Cohrent source \[{{I}_{\max }}=4l\]. \[\therefore \] for incohrent source \[I={{I}_{1}}+{{I}_{2}}=2l.\] \[\therefore \] Ratio \[=\frac{{{I}_{\max }}}{I{{'}_{\max }}}=2\]You need to login to perform this action.
You will be redirected in
3 sec