A) \[(10/4)\,A\]
B) \[(10/5)\,A\]
C) \[(10/12)\,A\]
D) \[(10/6)\,A\]
Correct Answer: B
Solution :
Initially, 1 offers infinity resistence \[\therefore \] \[{{I}_{1}}={{I}_{3}}=\frac{E}{{{R}_{1}}+{{R}_{2}}}=2A\]You need to login to perform this action.
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