A) \[66.6%\]
B) \[16.6%\]
C) \[33.3%\]
D) \[40%\]
Correct Answer: D
Solution :
At 300 K W gram of air is present in the flask. \[PV=\frac{W}{m}RT\] \[PV=\frac{W}{m}R\times 300\] ?.(i) When heated to 500 K, then air in flask = W gram \[PV=\frac{W'}{m}R\times 500\] ??(ii) From equations (i) and (ii) \[\frac{W}{m}R\times 300=\frac{W'}{m}R\times 500\] \[W'=\frac{3W}{5}\] Amount of air escaped \[=W-W'\] \[=W-\frac{3W}{5}=\frac{2W}{5}\] % of air escaped \[=\frac{2W}{5W}\times 100=40%\]You need to login to perform this action.
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