A) \[MH\]
B) \[2MH\]
C) \[27\pi MH\]
D) zero
Correct Answer: D
Solution :
From the relation, Work done \[=-MH\,(\cos {{\theta }_{f}}-\cos {{\theta }_{i}})\] \[W=MH\,(\cos {{360}^{o}}-\cos {{0}^{o}})\] W = zeroYou need to login to perform this action.
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