A) \[810\,\Omega \]
B) \[790\,\Omega \]
C) \[1020\,\Omega \]
D) \[480\,\Omega \]
Correct Answer: B
Solution :
Balanced \[V=x\]\[\times \] Balancing length \[10\times {{10}^{-3}}=x\times 40\times {{10}^{-2}}\] \[x=\frac{1}{40}V/m\] Now \[x=\frac{{{I}_{\omega }}{{R}_{\omega }}}{{{L}_{\omega }}}\] \[\left( \frac{2}{10+R} \right).\frac{10}{1}=\frac{1}{40}\] \[10+R=800\] \[R=790\Omega \]You need to login to perform this action.
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