A) \[\frac{{{m}_{1}}}{{{m}_{2}}}\,d\]
B) \[d\]
C) \[\frac{{{m}_{2}}}{{{m}_{1}}}\]
D) \[\frac{{{m}_{1}}}{{{m}_{1}}+{{m}_{2}}}\,d\]
Correct Answer: A
Solution :
\[{{m}_{1}}{{r}_{1}}={{m}_{2}}{{r}_{2}}\] ???(1) \[{{m}_{1}}({{r}_{1}}-d)={{m}_{2}}({{r}_{2}}-d')\] ??? (2) from (1) and (2) we get \[d'=\frac{{{m}_{1}}}{{{m}_{2}}}\,d\]You need to login to perform this action.
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