A) \[6E,\,\,6C\]
B) \[E,\,C\]
C) \[\frac{E}{6},\,6\,C\]
D) \[E,6C\]
Correct Answer: C
Solution :
\[{{C}_{PPC}}=\frac{{{\in }_{0}}{{\in }_{r}}A}{d}\] \[\Rightarrow \] \[C''=6C\] \[{{E}_{PPC}}=\frac{q}{{{\in }_{0}}{{\in }_{r}}A}\] \[\Rightarrow \] \[E'=\frac{E}{6}\]You need to login to perform this action.
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