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NEET Sample Paper NEET Sample Test Paper-29

  • question_answer
    The energy and capacity of a charged parallel plate capacitor are E and C respectively. Now a dielective slab of \[{{\in }_{r}}=6\] is inserted in it then energy and capacity becomes (Assuming charge on plates remains constant)

    A)  \[6E,\,\,6C\]                

    B)  \[E,\,C\]

    C)  \[\frac{E}{6},\,6\,C\]             

    D)  \[E,6C\]

    Correct Answer: C

    Solution :

    \[{{C}_{PPC}}=\frac{{{\in }_{0}}{{\in }_{r}}A}{d}\] \[\Rightarrow \] \[C''=6C\] \[{{E}_{PPC}}=\frac{q}{{{\in }_{0}}{{\in }_{r}}A}\] \[\Rightarrow \] \[E'=\frac{E}{6}\]


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