A) \[\frac{2}{3}\,E\]
B) \[\frac{1}{8}\,E\]
C) \[\frac{1}{4}\,E\]
D) \[\frac{1}{2}\,E\]
Correct Answer: C
Solution :
\[PE=\frac{1}{2}K{{x}^{2}}=\frac{1}{2}K{{\left( \frac{a}{2} \right)}^{2}}=\frac{E}{4}\]You need to login to perform this action.
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