A) \[0.5\times {{10}^{16}}\]
B) \[2\times {{10}^{16}}\]
C) \[3.5\times {{10}^{16}}\]
D) \[1\times {{10}^{16}}\]
Correct Answer: C
Solution :
\[t=nT,\] \[X=\frac{{{X}_{0}}}{{{2}^{n}}},\] \[n=\frac{t}{T}=\frac{30}{10}=3\] Active nuclei \[X=\frac{4\times {{10}^{16}}}{{{(2)}^{3}}}\]and decayed nuclei \[X'=({{X}_{0}}-X)=3.5\times {{10}^{16}}\]You need to login to perform this action.
You will be redirected in
3 sec