A) \[\frac{n}{4}\]
B) \[\sqrt{2}\,n\]
C) \[n\]
D) \[\frac{n}{\sqrt{2}}\]
Correct Answer: C
Solution :
\[n=\frac{1}{2\,\ell }\sqrt{\frac{2T}{\pi {{(2r)}^{2}}\frac{\rho }{2}}}=\frac{1}{2\ell }\,\sqrt{\frac{T}{\pi {{r}^{3}}\rho }}=n\] \[\Rightarrow \] No changeYou need to login to perform this action.
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