A) \[1:4\]
B) \[1:1\]
C) \[1:8\]
D) \[4:1\]
Correct Answer: A
Solution :
\[{{B}_{1}}=\frac{{{\mu }_{0}}I}{2R}\times N=\frac{{{\mu }_{0}}I\pi }{L};\] \[{{B}_{2}}=\frac{{{\mu }_{0}}I}{2{{R}_{1}}}\times 2=\frac{4{{\mu }_{0}}I\pi }{L}\] \[\Rightarrow \]\[\]You need to login to perform this action.
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