A) r
B) \[0.5\,r\]
C) \[2\,r\]
D) \[3\,r\]
Correct Answer: B
Solution :
From the analysis of figure (I). It is evident that the potential difference between points a, b and c is zero. The equivalent circuit is as shown in figure (ii). \[\Rightarrow \] \[{{r}_{gF}}={{r}_{de}}=\frac{2r\times 2r}{2r+2r}=r\] \[{{r}_{AB}}=\frac{2r\times 2r}{2r+2r}=\frac{r}{2}=0.5r.\]You need to login to perform this action.
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