NEET Sample Paper NEET Sample Test Paper-2

  • question_answer
    A simple pendulum with a solid metal bob has a period T. The metal bob is now immersed in a liquid of density one-tenth that of the bob. The liquid is non viscous. Now the period of the same pendulum with its bob remaining all the time in the liquid will be:

    A)  \[T\]                 

    B)  \[\left( \frac{9}{10} \right)T\]

    C)  \[\sqrt{\frac{10}{9}}T\]

    D)  \[\sqrt{\frac{9}{10}}T\]

    Correct Answer: C

    Solution :

    Apparent acceleration due to gravity because of force of buoyancy \[g'=g\left( 1-\frac{{{P}_{l}}}{{{P}_{s}}} \right){{P}_{l}}=\frac{{{P}_{s}}}{10}\] \[\Rightarrow \] \[g'=g\left( 1-\frac{1}{10} \right)=\frac{9}{10}g\] As, we know that for simple pendulum, \[T=2\pi \sqrt{\frac{L}{g}}\] \[T\alpha \sqrt{\frac{L}{g}}\]    \[\Rightarrow \]   \[T'=\sqrt{\frac{10}{9}}\,T\]


You need to login to perform this action.
You will be redirected in 3 sec spinner