A) \[\Delta E+2RT\]
B) \[\Delta E-2RT\]
C) \[\Delta E+RT\]
D) \[\Delta E-RT\]
Correct Answer: B
Solution :
\[\Delta H=\Delta E+\Delta ngRT\] For the reaction, \[{{N}_{2(g)}}+3{{H}_{2(g)}}2N{{H}_{3(g)}}\] \[\Delta {{n}_{g}}=2-4=-2\] \[\Delta H=\Delta E+(-2)RT\] \[\Delta H=\Delta E-2RT\]You need to login to perform this action.
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