A) \[0.4\]
B) \[0.2\]
C) \[0.8\]
D) \[0.6\]
Correct Answer: D
Solution :
Power factor, \[\cos \phi =\frac{R}{Z}\] \[=\frac{20+40}{\sqrt{{{60}^{2}}+{{(100-20)}^{2}}}}=\frac{60}{100}=0.6\] [as, \[({{X}_{L}}-{{X}_{C}})=100-20=80\]] \[({{R}_{eq}}=20+40=60\Omega \])
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