A) \[S{{F}_{4}}\] and \[{{S}_{2}}{{F}_{2}}\]
B) \[S{{F}_{4}}\] and \[S{{F}_{6}}\]
C) \[S{{F}_{6}}\] and \[S{{F}_{4}}\]
D) \[NaF\] and \[NaCl\]
Correct Answer: C
Solution :
Yellow powder is sulphur. Colourless gas (X) having octahedral structure is \[S{{F}_{6}}\]. Colourless gas (Y) is \[S{{F}_{4}}\]. \[\underset{\begin{smallmatrix} Yellow \\ powder \end{smallmatrix}}{\mathop{S}}\,+3{{F}_{2}}\xrightarrow{\Delta }\underset{(X)\,colourless\,gas}{\mathop{S{{F}_{6}}}}\,\] \[3SC{{l}_{2}}+4NaF\xrightarrow{\Delta }\underset{(Y)\,Colourless}{\mathop{S{{F}_{4}}}}\,+{{S}_{2}}C{{l}_{2}}+4NaCl\]
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