A) zero
B) \[IB{{l}^{2}}\]
C) \[\sqrt{\frac{3}{2}}IB{{l}^{2}}\]
D) \[\sqrt{\frac{3}{4}}IB{{l}^{2}}\]
Correct Answer: D
Solution :
Any closed current loop in a magnetic field has net force on it, is equal to zero however it may have a net torque (momentum) on it, due to couple of forces. Since, \[\theta ={{90}^{o}}\] Hence \[\tau =NIAB=I\times I\times \left( \frac{\sqrt{3}}{4}{{l}^{2}} \right)B=\frac{\sqrt{3I}}{4}{{l}^{2}}B\]You need to login to perform this action.
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