A) \[\frac{mg}{K}\]
B) \[\frac{qE}{K}\]
C) \[\frac{mg+qE}{K}\]
D) \[\frac{mg-qE}{K}\]
Correct Answer: D
Solution :
From the free body diagram as shown below \[qE+K{{K}_{O}}=mg\] \[\therefore \] \[{{X}_{O}}=\frac{mg-qE}{K}\]You need to login to perform this action.
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