A) carbanion
B) carbene
C) free radical
D) carbocation
Correct Answer: D
Solution :
\[{{C}_{6}}{{H}_{5}}-\underset{H}{\mathop{\underset{|}{\mathop{\overset{Cl}{\mathop{\overset{|}{\mathop{C}}\,}}\,}}\,}}\,-C{{H}_{3}}+SbC{{l}_{3}}\underset{Carbocation}{\mathop{{{C}_{6}}{{H}_{5}}-\overset{+}{\mathop{\underset{H}{\mathop{\underset{|}{\mathop{C}}\,}}\,}}\,-C{{H}_{3}}+SbCl_{6}^{-}}}\,\] The planar carbonation, when return back form racemic mixture of the starting compounds.You need to login to perform this action.
You will be redirected in
3 sec