A) \[X=C{{O}_{2}}\text{,}Y=C{{l}_{2}}\]
B) \[X=C{{l}_{2}}\text{,}Y=C{{O}_{2}}\]
C) \[X=C{{l}_{2}},Y={{H}_{2}}\]
D) \[X={{H}_{2}},Y=C{{l}_{2}}\]
Correct Answer: C
Solution :
\[\underset{(X)}{\mathop{C{{l}_{2}}}}\,+{{H}_{2}}O\xrightarrow{{}}HCl+HOCl\] \[HCl+AgN{{O}_{3}}\xrightarrow{{}}\underset{white}{\mathop{AgCl}}\,\downarrow +HN{{O}_{3}}\] \[2HCl+Mg\xrightarrow{{}}MgC{{l}_{2}}+{{H}_{2(g)}}\uparrow \]You need to login to perform this action.
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