A) \[8.2\,T\]
B) \[2.8\,T\]
C) \[5.6\,T\]
D) \[8.4\,T\]
Correct Answer: B
Solution :
According to Krpler's third law \[{{T}^{2}}\propto {{R}^{3}}\] For two cases, we have \[{{\left[ \frac{{{T}_{2}}}{{{T}_{2}}} \right]}^{2}}={{\left[ \frac{R}{2R} \right]}^{3}}\] \[\Rightarrow \] \[\frac{{{T}_{1}}}{{{T}_{2}}}={{\left( \frac{1}{2} \right)}^{3/2}}\] \[\Rightarrow \] \[{{T}_{2}}={{(2)}^{3/2}}{{T}_{1}}\] \[\therefore \] \[{{T}_{2}}=2.8\,{{T}_{1}}\]
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