A) \[1\times {{10}^{2}}c{{m}^{3}}\]
B) \[2\times {{10}^{2}}c{{m}^{3}}\]
C) \[1.764\times {{10}^{2}}c{{m}^{3}}\]
D) None of these
Correct Answer: B
Solution :
From the formula, volume (V) = length (L) \[\times \] breadth (b11) \[\times \] thickness (h) Here \[l=12cm,\,\,b=6cm\] \[h=2.45\,cm\] \[=12\times 6\times 2.45=176.4c{{m}^{3}}\] \[=1.764\times {{10}^{2}}c{{m}^{3}}.\] Hence, I, b and h the minimum number of significant figure is 1 in breadth. So, the volume will contain only one significant figure. So, \[V=2\times {{10}^{2}}c{{m}^{3}}.\]
You need to login to perform this action.
You will be redirected in
3 sec
