A) 1200 mg
B) 3600mg
C) 4800 mg
D) 2400mg
Correct Answer: D
Solution :
\[T=n\times {{t}_{{\scriptstyle{}^{1}/{}_{2}}}}\] \[n=\frac{T}{{{t}_{{\scriptstyle{}^{1}/{}_{2}}}}}=\frac{9.2}{2.3}=4\] \[\frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{n}}\] \[\frac{300}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{4}}=\frac{1}{8}\] \[{{N}_{0}}=300\times 8=2400\,mg\]You need to login to perform this action.
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