A) \[0.6\]Joule
B) \[0.06\]Joule
C) \[0.03\]Joule
D) \[0.3\]Joule
Correct Answer: C
Solution :
The energy stored in capacitor is given by \[U=\frac{1}{2}C{{V}^{2}}\] Here \[C=6\times {{10}^{-6}}F,\] \[V=100\] volt \[U=\frac{1}{2}\times 6\times {{10}^{-6}}\times {{(100)}^{2}}\] \[\Rightarrow \] \[U=3\times {{10}^{-2}}J=0.03\,J\]You need to login to perform this action.
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