A) 4
B) 2
C) 16
D) 8
Correct Answer: C
Solution :
According to Stefan's law for radiated energy \[E\propto {{T}^{4}}\] For two cases we have, \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{T_{1}^{4}}{T_{2}^{4}}\] Here, \[{{T}_{1}}=T,\,{{T}_{2}}=2T\] \[\frac{{{E}_{1}}}{{{E}_{2}}}={{\left( \frac{T}{2T} \right)}^{4}}=\frac{1}{16}\] \[{{E}_{2}}=16{{E}_{1}}\]You need to login to perform this action.
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