A) 20%
B) 35%
C) 10%
D) 25%
Correct Answer: B
Solution :
The percentage of volume of ice-cube outside the water is given by \[=\frac{\Delta V}{V}\times 100\] \[=\frac{{{P}_{water}}-{{P}_{ice}}}{{{P}_{water}}}\times 100\] Here, \[{{P}_{water}}=1000kg/{{m}^{3}}\] \[{{P}_{ice}}=900kg/{{m}^{3}}\] \[\therefore \] % in volume \[=\frac{1000-900}{1000}\times 100=10%\]You need to login to perform this action.
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