A) increase by 4 times
B) decrease by 2 times
C) increase by 2 times
D) remains the same
Correct Answer: C
Solution :
\[2A+B\xrightarrow{{}}{{A}_{2}}B\] \[r=K{{[A]}^{2}}[B]\] If the concentration of A is doubled and B is halved, then \[r'=K{{[2A]}^{2}}\left[ \frac{B}{2} \right]=2K{{[A]}^{2}}[B]\] \[r'=2r\]You need to login to perform this action.
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