I. \[O{{F}_{2}}\] |
II. \[{{O}_{2}}\] |
III. \[{{H}_{2}}O\] |
IV. NaF |
A) I, III and IV
B) II and III
C) II, III and IV
D) all of the above
Correct Answer: C
Solution :
Fluorine does not form oxyacids as it is the most electronegative element. \[2{{F}_{2}}+4NaOH\xrightarrow{{}}4NaF+{{O}_{2}}+2{{H}_{2}}O\]You need to login to perform this action.
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