A) \[2V\]
B) V
C) \[\frac{b}{a}\,V\]
D) \[\frac{a}{b}\,V\]
Correct Answer: D
Solution :
\[V=\frac{KQ}{a}\] and when connected by wire charge of A will transfer to B so potential \[V'=\frac{KQ}{b}=\frac{a}{b}V\]You need to login to perform this action.
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