A) 64W
B) 100W
C) 32W
D) 50W
Correct Answer: A
Solution :
\[P={{\left( \frac{{{V}_{S}}}{{{V}_{P}}} \right)}^{2}}W={{\left( \frac{160}{200} \right)}^{2}}100=64\,W\]You need to login to perform this action.
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