A) \[\frac{{{\mu }_{0}}I}{12\pi }\]
B) \[\frac{{{\mu }_{0}}I}{24\pi }\]
C) \[\frac{{{\mu }_{0}}I}{48\pi }\]
D) \[\frac{{{\mu }_{0}}I}{6\pi }\]
Correct Answer: B
Solution :
\[{{B}_{1}}=\frac{{{\mu }_{0}}I}{2\pi (4)}\odot \] \[{{B}_{2}}=\frac{{{\mu }_{0}}I}{2\pi (3)}\otimes \] \[B=\frac{{{\mu }_{0}}I}{2\pi }\left[ \frac{1}{3}-\frac{1}{4} \right]=\frac{{{\mu }_{0}}I}{24\pi }\]You need to login to perform this action.
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