A) \[{{10}^{-3.8}}\]
B) \[{{10}^{-3.2}}\]
C) \[{{10}^{-10.8}}\]
D) \[{{10}^{-10.2}}\]
Correct Answer: C
Solution :
\[pH=3.2\Rightarrow pOH=14-3.2=10.8\] \[\Rightarrow \] \[-\log \,[O{{H}^{-}}]=10.8\] \[\Rightarrow \] \[\,[O{{H}^{-}}]={{10}^{-10.8}}\]You need to login to perform this action.
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