A) \[2\pi \sqrt{\frac{R}{g}}\]
B) \[2\pi \sqrt{\frac{2R}{g}}\]
C) \[2\pi \sqrt{\frac{R}{2g}}\]
D) \[2\pi \sqrt{\frac{3R}{2g}}\]
Correct Answer: B
Solution :
\[T=2\pi \sqrt{\frac{\ell +\frac{{{K}^{2}}}{\ell }}{g}}\] Here \[\ell =R,\]\[M{{K}^{2}}=M{{R}^{2}}\Rightarrow K=R\] \[\Rightarrow \] \[T=2\pi \sqrt{\frac{R+R}{g}}=2\pi \sqrt{\frac{2R}{g}}\]You need to login to perform this action.
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